(2x-16)+(x+40)+(x)=180

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Solution for (2x-16)+(x+40)+(x)=180 equation: 



(2x-16)+(x+40)+(x)=180

We move all terms to the left:

(2x-16)+(x+40)+(x)-(180)=0

We add all the numbers together, and all the variables

x+(2x-16)+(x+40)-180=0

We get rid of parentheses

x+2x+x-16+40-180=0

We add all the numbers together, and all the variables

4x-156=0

We move all terms containing x to the left, all other terms to the right

4x=156

x=156/4

x=39

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