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(2x-15)=(5x+55)
We move all terms to the left:
(2x-15)-((5x+55))=0
We get rid of parentheses
2x-((5x+55))-15=0
We calculate terms in parentheses: -((5x+55)), so:We get rid of parentheses
(5x+55)
We get rid of parentheses
5x+55
Back to the equation:
-(5x+55)
2x-5x-55-15=0
We add all the numbers together, and all the variables
-3x-70=0
We move all terms containing x to the left, all other terms to the right
-3x=70
x=70/-3
x=-23+1/3
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