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(2x-15)(x+17)=0
We multiply parentheses ..
(+2x^2+34x-15x-255)=0
We get rid of parentheses
2x^2+34x-15x-255=0
We add all the numbers together, and all the variables
2x^2+19x-255=0
a = 2; b = 19; c = -255;
Δ = b2-4ac
Δ = 192-4·2·(-255)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-49}{2*2}=\frac{-68}{4} =-17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+49}{2*2}=\frac{30}{4} =7+1/2 $
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