(2x-14)(x-7)=0

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Solution for (2x-14)(x-7)=0 equation: 



(2x-14)(x-7)=0

We multiply parentheses ..

(+2x^2-14x-14x+98)=0

We get rid of parentheses

2x^2-14x-14x+98=0

We add all the numbers together, and all the variables

2x^2-28x+98=0

a = 2; b = -28; c = +98;
Δ = b2-4ac
Δ = -282-4·2·98
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{28}{4}=7$

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