(2x-12)=(3x+22)

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Solution for (2x-12)=(3x+22) equation: 



(2x-12)=(3x+22)

We move all terms to the left:

(2x-12)-((3x+22))=0

We get rid of parentheses

2x-((3x+22))-12=0



We calculate terms in parentheses: -((3x+22)), so:

(3x+22)

We get rid of parentheses

3x+22

Back to the equation:

-(3x+22)



We get rid of parentheses

2x-3x-22-12=0

We add all the numbers together, and all the variables

-1x-34=0

We move all terms containing x to the left, all other terms to the right

-x=34

x=34/-1

x=-34

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