(2x-12)(2x-12)=0

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Solution for (2x-12)(2x-12)=0 equation: 



(2x-12)(2x-12)=0

We multiply parentheses ..

(+4x^2-24x-24x+144)=0

We get rid of parentheses

4x^2-24x-24x+144=0

We add all the numbers together, and all the variables

4x^2-48x+144=0

a = 4; b = -48; c = +144;
Δ = b2-4ac
Δ = -482-4·4·144
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{48}{8}=6$

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