(2x-10)=x(x+3)

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Solution for (2x-10)=x(x+3) equation: 



(2x-10)=x(x+3)

We move all terms to the left:

(2x-10)-(x(x+3))=0

We get rid of parentheses

2x-(x(x+3))-10=0



We calculate terms in parentheses: -(x(x+3)), so:

x(x+3)

We multiply parentheses

x^2+3x

Back to the equation:

-(x^2+3x)



We get rid of parentheses

-x^2+2x-3x-10=0

We add all the numbers together, and all the variables

-1x^2-1x-10=0

a = -1; b = -1; c = -10;
Δ = b2-4ac
Δ = -12-4·(-1)·(-10)
Δ = -39
Delta is less than zero, so there is no solution for the equation

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