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(2x-10)=(5x+52)
We move all terms to the left:
(2x-10)-((5x+52))=0
We get rid of parentheses
2x-((5x+52))-10=0
We calculate terms in parentheses: -((5x+52)), so:We get rid of parentheses
(5x+52)
We get rid of parentheses
5x+52
Back to the equation:
-(5x+52)
2x-5x-52-10=0
We add all the numbers together, and all the variables
-3x-62=0
We move all terms containing x to the left, all other terms to the right
-3x=62
x=62/-3
x=-20+2/3
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