(2x-1)x=(x+2)(2x-4)

Solution for (2x-1)x=(x+2)(2x-4) equation:

(2x-1)x=(x+2)(2x-4)

We move all terms to the left:

(2x-1)x-((x+2)(2x-4))=0

We multiply parentheses

2x^2-1x-((x+2)(2x-4))=0

We multiply parentheses ..

2x^2-((+2x^2-4x+4x-8))-1x=0


We calculate terms in parentheses: -((+2x^2-4x+4x-8)), so:

(+2x^2-4x+4x-8)

We get rid of parentheses

2x^2-4x+4x-8

We add all the numbers together, and all the variables

2x^2-8

Back to the equation:

-(2x^2-8)


We add all the numbers together, and all the variables

2x^2-1x-(2x^2-8)=0

We get rid of parentheses

2x^2-2x^2-1x+8=0

We add all the numbers together, and all the variables

-1x+8=0

We move all terms containing x to the left, all other terms to the right

-x=-8

x=-8/-1

x=+8