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(2x-1)5x+72=180
We move all terms to the left:
(2x-1)5x+72-(180)=0
We add all the numbers together, and all the variables
(2x-1)5x-108=0
We multiply parentheses
10x^2-5x-108=0
a = 10; b = -5; c = -108;
Δ = b2-4ac
Δ = -52-4·10·(-108)
Δ = 4345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{4345}}{2*10}=\frac{5-\sqrt{4345}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{4345}}{2*10}=\frac{5+\sqrt{4345}}{20} $
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