(2x-1)/4=(x-7)/3

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Solution for (2x-1)/4=(x-7)/3 equation: 



(2x-1)/4=(x-7)/3

We move all terms to the left:

(2x-1)/4-((x-7)/3)=0

We calculate fractions


2x/()+(-((x-7)*4)/()=0



We calculate terms in parentheses: +(-((x-7)*4)/(), so:

-((x-7)*4)/(

We multiply all the terms by the denominator


-((x-7)*4)



We calculate terms in parentheses: -((x-7)*4), so:

(x-7)*4

We multiply parentheses

4x-28

Back to the equation:

-(4x-28)



We get rid of parentheses

-4x+28

Back to the equation:

+(-4x+28)



We get rid of parentheses

2x/()-4x+28=0

We multiply all the terms by the denominator


2x-4x*()+28*()=0

We add all the numbers together, and all the variables

2x-4x*()=0

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