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(2x-1)/(x+4)-(2x-5)/(x-3)=0
Domain of the equation: (x+4)!=0
We move all terms containing x to the left, all other terms to the right
x!=-4
x∈R
Domain of the equation: (x-3)!=0We calculate fractions
We move all terms containing x to the left, all other terms to the right
x!=3
x∈R
((2x-1)*(x-3))/((x+4)*(x-3))+(-(2x-5)*(x+4))/((x+4)*(x-3))=0
We calculate terms in parentheses: +((2x-1)*(x-3))/((x+4)*(x-3)), so:
(2x-1)*(x-3))/((x+4)*(x-3)
We multiply all the terms by the denominator
(2x-1)*(x-3))
Back to the equation:
+((2x-1)*(x-3)))
We calculate terms in parentheses: +(-(2x-5)*(x+4))/((x+4)*(x-3)), so:
-(2x-5)*(x+4))/((x+4)*(x-3)
We multiply all the terms by the denominator
-(2x-5)*(x+4))
Back to the equation:
+(-(2x-5)*(x+4)))
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