(2x-1)+3(x-5)=-2(2x-+1)

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Solution for (2x-1)+3(x-5)=-2(2x-+1) equation: 



(2x-1)+3(x-5)=-2(2x-+1)

We move all terms to the left:

(2x-1)+3(x-5)-(-2(2x-+1))=0

We add all the numbers together, and all the variables

(2x-1)+3(x-5)-(-2(+2x))=0

We multiply parentheses

(2x-1)+3x-(-2(+2x))-15=0

We get rid of parentheses

2x+3x-(-2(+2x))-1-15=0



We calculate terms in parentheses: -(-2(+2x)), so:

-2(+2x)

We multiply parentheses

-4x

Back to the equation:

-(-4x)



We add all the numbers together, and all the variables

5x-(-4x)-16=0

We get rid of parentheses

5x+4x-16=0

We add all the numbers together, and all the variables

9x-16=0

We move all terms containing x to the left, all other terms to the right

9x=16

x=16/9

x=1+7/9

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