(2x-1)+(x+5)=2(x+2)(x-2)

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Solution for (2x-1)+(x+5)=2(x+2)(x-2) equation: 



(2x-1)+(x+5)=2(x+2)(x-2)

We move all terms to the left:

(2x-1)+(x+5)-(2(x+2)(x-2))=0

We use the square of the difference formula

x^2+(2x-1)+(x+5)+4=0

We get rid of parentheses

x^2+2x+x-1+5+4=0

We add all the numbers together, and all the variables

x^2+3x+8=0

a = 1; b = 3; c = +8;
Δ = b2-4ac
Δ = 32-4·1·8
Δ = -23
Delta is less than zero, so there is no solution for the equation

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