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(2x-1)(x+6)=172
We move all terms to the left:
(2x-1)(x+6)-(172)=0
We multiply parentheses ..
(+2x^2+12x-1x-6)-172=0
We get rid of parentheses
2x^2+12x-1x-6-172=0
We add all the numbers together, and all the variables
2x^2+11x-178=0
a = 2; b = 11; c = -178;
Δ = b2-4ac
Δ = 112-4·2·(-178)
Δ = 1545
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{1545}}{2*2}=\frac{-11-\sqrt{1545}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{1545}}{2*2}=\frac{-11+\sqrt{1545}}{4} $
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