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(2x-1)(x+2)-x/2=-2
We move all terms to the left:
(2x-1)(x+2)-x/2-(-2)=0
We add all the numbers together, and all the variables
(2x-1)(x+2)-x/2+2=0
We multiply parentheses ..
(+2x^2+4x-1x-2)-x/2+2=0
We multiply all the terms by the denominator
((+2x^2+4x-1x-2))*2-x+2*2=0
We add all the numbers together, and all the variables
((+2x^2+4x-1x-2))*2-1x+4=0
We move all terms containing x to the left, all other terms to the right
((+2x^2+4x-1x-2))*2-1x=-4
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