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(2x-1)(5x+20)=0
We multiply parentheses ..
(+10x^2+40x-5x-20)=0
We get rid of parentheses
10x^2+40x-5x-20=0
We add all the numbers together, and all the variables
10x^2+35x-20=0
a = 10; b = 35; c = -20;
Δ = b2-4ac
Δ = 352-4·10·(-20)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-45}{2*10}=\frac{-80}{20} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+45}{2*10}=\frac{10}{20} =1/2 $
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