(2x-1)(4x2+2x+1)-(2x+5)(4x2-7)=41x2

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Solution for (2x-1)(4x2+2x+1)-(2x+5)(4x2-7)=41x2 equation: 



(2x-1)(4x^2+2x+1)-(2x+5)(4x^2-7)=41x^2

We move all terms to the left:

(2x-1)(4x^2+2x+1)-(2x+5)(4x^2-7)-(41x^2)=0

determiningTheFunctionDomain
-41x^2+(2x-1)(4x^2+2x+1)-(2x+5)(4x^2-7)=0

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