(2x-1)(4x-4)=0

Solution for (2x-1)(4x-4)=0 equation:

(2x-1)(4x-4)=0

We multiply parentheses ..

(+8x^2-8x-4x+4)=0

We get rid of parentheses

8x^2-8x-4x+4=0

We add all the numbers together, and all the variables

8x^2-12x+4=0

a = 8; b = -12; c = +4;
Δ = b2-4ac
Δ = -122-4·8·4
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4}{2*8}=\frac{8}{16}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4}{2*8}=\frac{16}{16}
=1
$