(2x-1)(4x-1)=(2x+1)(4x+1)

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Solution for (2x-1)(4x-1)=(2x+1)(4x+1) equation:



(2x-1)(4x-1)=(2x+1)(4x+1)
We move all terms to the left:
(2x-1)(4x-1)-((2x+1)(4x+1))=0
We multiply parentheses ..
(+8x^2-2x-4x+1)-((2x+1)(4x+1))=0
We calculate terms in parentheses: -((2x+1)(4x+1)), so:
(2x+1)(4x+1)
We multiply parentheses ..
(+8x^2+2x+4x+1)
We get rid of parentheses
8x^2+2x+4x+1
We add all the numbers together, and all the variables
8x^2+6x+1
Back to the equation:
-(8x^2+6x+1)
We get rid of parentheses
8x^2-8x^2-2x-4x-6x+1-1=0
We add all the numbers together, and all the variables
-12x=0
x=0/-12
x=0

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