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(2x-1)(4x+1)=8
We move all terms to the left:
(2x-1)(4x+1)-(8)=0
We multiply parentheses ..
(+8x^2+2x-4x-1)-8=0
We get rid of parentheses
8x^2+2x-4x-1-8=0
We add all the numbers together, and all the variables
8x^2-2x-9=0
a = 8; b = -2; c = -9;
Δ = b2-4ac
Δ = -22-4·8·(-9)
Δ = 292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{292}=\sqrt{4*73}=\sqrt{4}*\sqrt{73}=2\sqrt{73}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{73}}{2*8}=\frac{2-2\sqrt{73}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{73}}{2*8}=\frac{2+2\sqrt{73}}{16} $
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