(2x-1)(2x+1)=8

Solution for (2x-1)(2x+1)=8 equation:

Simplifying
(2x + -1)(2x + 1) = 8

Reorder the terms:
(-1 + 2x)(2x + 1) = 8

Reorder the terms:
(-1 + 2x)(1 + 2x) = 8

Multiply (-1 + 2x) * (1 + 2x)
(-1(1 + 2x) + 2x * (1 + 2x)) = 8
((1 * -1 + 2x * -1) + 2x * (1 + 2x)) = 8
((-1 + -2x) + 2x * (1 + 2x)) = 8
(-1 + -2x + (1 * 2x + 2x * 2x)) = 8
(-1 + -2x + (2x + 4x2)) = 8

Combine like terms: -2x + 2x = 0
(-1 + 0 + 4x2) = 8
(-1 + 4x2) = 8

Solving
-1 + 4x2 = 8

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 4x2 = 8 + 1

Combine like terms: -1 + 1 = 0
0 + 4x2 = 8 + 1
4x2 = 8 + 1

Combine like terms: 8 + 1 = 9
4x2 = 9

Divide each side by '4'.
x2 = 2.25

Simplifying
x2 = 2.25

Take the square root of each side:
x = {-1.5, 1.5}