(2x-1)(10)=(3x+1)(5)

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Solution for (2x-1)(10)=(3x+1)(5) equation: 



(2x-1)(10)=(3x+1)(5)

We move all terms to the left:

(2x-1)(10)-((3x+1)(5))=0

We multiply parentheses

20x-((3x+1)5)-10=0



We calculate terms in parentheses: -((3x+1)5), so:

(3x+1)5

We multiply parentheses

15x+5

Back to the equation:

-(15x+5)



We get rid of parentheses

20x-15x-5-10=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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