(2x-)-4(x-5)=(1-2x)(x-1)

Solution for (2x-)-4(x-5)=(1-2x)(x-1) equation:

(2x-)-4(x-5)=(1-2x)(x-1)

We move all terms to the left:

(2x-)-4(x-5)-((1-2x)(x-1))=0

We add all the numbers together, and all the variables

(+2x)-4(x-5)-((-2x+1)(x-1))=0

We multiply parentheses

(+2x)-4x-((-2x+1)(x-1))+20=0

We get rid of parentheses

2x-4x-((-2x+1)(x-1))+20=0

We multiply parentheses ..

-((-2x^2+2x+x-1))+2x-4x+20=0


We calculate terms in parentheses: -((-2x^2+2x+x-1)), so:

(-2x^2+2x+x-1)

We get rid of parentheses

-2x^2+2x+x-1

We add all the numbers together, and all the variables

-2x^2+3x-1

Back to the equation:

-(-2x^2+3x-1)


We add all the numbers together, and all the variables

-(-2x^2+3x-1)-2x+20=0

We get rid of parentheses

2x^2-3x-2x+1+20=0

We add all the numbers together, and all the variables

2x^2-5x+21=0

a = 2; b = -5; c = +21;
Δ = b2-4ac
Δ = -52-4·2·21
Δ = -143
Delta is less than zero, so there is no solution for the equation