(2x+9)*(x-5)=50

Solution for (2x+9)*(x-5)=50 equation:

(2x+9)(x-5)=50

We move all terms to the left:

(2x+9)(x-5)-(50)=0

We multiply parentheses ..

(+2x^2-10x+9x-45)-50=0

We get rid of parentheses

2x^2-10x+9x-45-50=0

We add all the numbers together, and all the variables

2x^2-1x-95=0

a = 2; b = -1; c = -95;
Δ = b2-4ac
Δ = -12-4·2·(-95)
Δ = 761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{761}}{2*2}=\frac{1-\sqrt{761}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{761}}{2*2}=\frac{1+\sqrt{761}}{4}
$