(2x+9)(x-7)=0

Solution for (2x+9)(x-7)=0 equation:

(2x+9)(x-7)=0

We multiply parentheses ..

(+2x^2-14x+9x-63)=0

We get rid of parentheses

2x^2-14x+9x-63=0

We add all the numbers together, and all the variables

2x^2-5x-63=0

a = 2; b = -5; c = -63;
Δ = b2-4ac
Δ = -52-4·2·(-63)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-23}{2*2}=\frac{-18}{4}
=-4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+23}{2*2}=\frac{28}{4}
=7
$