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(2x+9)(x+7)=()
We move all terms to the left:
(2x+9)(x+7)-(())=0
We add all the numbers together, and all the variables
(2x+9)(x+7)=0
We multiply parentheses ..
(+2x^2+14x+9x+63)=0
We get rid of parentheses
2x^2+14x+9x+63=0
We add all the numbers together, and all the variables
2x^2+23x+63=0
a = 2; b = 23; c = +63;
Δ = b2-4ac
Δ = 232-4·2·63
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-5}{2*2}=\frac{-28}{4} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+5}{2*2}=\frac{-18}{4} =-4+1/2 $
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