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(2x+9)(x)=320
We move all terms to the left:
(2x+9)(x)-(320)=0
We multiply parentheses
2x^2+9x-320=0
a = 2; b = 9; c = -320;
Δ = b2-4ac
Δ = 92-4·2·(-320)
Δ = 2641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{2641}}{2*2}=\frac{-9-\sqrt{2641}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{2641}}{2*2}=\frac{-9+\sqrt{2641}}{4} $
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