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(2x+9)(7x-2)=0
We multiply parentheses ..
(+14x^2-4x+63x-18)=0
We get rid of parentheses
14x^2-4x+63x-18=0
We add all the numbers together, and all the variables
14x^2+59x-18=0
a = 14; b = 59; c = -18;
Δ = b2-4ac
Δ = 592-4·14·(-18)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4489}=67$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(59)-67}{2*14}=\frac{-126}{28} =-4+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(59)+67}{2*14}=\frac{8}{28} =2/7 $
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