(2x+8)*(x-3)=(x+6)*(2x-4)

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Solution for (2x+8)*(x-3)=(x+6)*(2x-4) equation: 



(2x+8)(x-3)=(x+6)(2x-4)

We move all terms to the left:

(2x+8)(x-3)-((x+6)(2x-4))=0

We multiply parentheses ..

(+2x^2-6x+8x-24)-((x+6)(2x-4))=0



We calculate terms in parentheses: -((x+6)(2x-4)), so:

(x+6)(2x-4)

We multiply parentheses ..

(+2x^2-4x+12x-24)

We get rid of parentheses

2x^2-4x+12x-24

We add all the numbers together, and all the variables

2x^2+8x-24

Back to the equation:

-(2x^2+8x-24)



We get rid of parentheses

2x^2-2x^2-6x+8x-8x-24+24=0

We add all the numbers together, and all the variables

-6x=0

x=0/-6

x=0

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