(2x+8)(2x+8)=180

Solution for (2x+8)(2x+8)=180 equation:

(2x+8)(2x+8)=180

We move all terms to the left:

(2x+8)(2x+8)-(180)=0

We multiply parentheses ..

(+4x^2+16x+16x+64)-180=0

We get rid of parentheses

4x^2+16x+16x+64-180=0

We add all the numbers together, and all the variables

4x^2+32x-116=0

a = 4; b = 32; c = -116;
Δ = b2-4ac
Δ = 322-4·4·(-116)
Δ = 2880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2880}=\sqrt{576*5}=\sqrt{576}*\sqrt{5}=24\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-24\sqrt{5}}{2*4}=\frac{-32-24\sqrt{5}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+24\sqrt{5}}{2*4}=\frac{-32+24\sqrt{5}}{8}
$