(2x+8)(2x+12)=96

Solution for (2x+8)(2x+12)=96 equation:

(2x+8)(2x+12)=96

We move all terms to the left:

(2x+8)(2x+12)-(96)=0

We multiply parentheses ..

(+4x^2+24x+16x+96)-96=0

We get rid of parentheses

4x^2+24x+16x+96-96=0

We add all the numbers together, and all the variables

4x^2+40x=0

a = 4; b = 40; c = 0;
Δ = b2-4ac
Δ = 402-4·4·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-40}{2*4}=\frac{-80}{8}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+40}{2*4}=\frac{0}{8}
=0
$