(2x+7z)(2x-7z)=0

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Solution for (2x+7z)(2x-7z)=0 equation:


Simplifying
(2x + 7z)(2x + -7z) = 0

Multiply (2x + 7z) * (2x + -7z)
(2x * (2x + -7z) + 7z * (2x + -7z)) = 0
((2x * 2x + -7z * 2x) + 7z * (2x + -7z)) = 0

Reorder the terms:
((-14xz + 4x2) + 7z * (2x + -7z)) = 0
((-14xz + 4x2) + 7z * (2x + -7z)) = 0
(-14xz + 4x2 + (2x * 7z + -7z * 7z)) = 0
(-14xz + 4x2 + (14xz + -49z2)) = 0

Reorder the terms:
(-14xz + 14xz + 4x2 + -49z2) = 0

Combine like terms: -14xz + 14xz = 0
(0 + 4x2 + -49z2) = 0
(4x2 + -49z2) = 0

Solving
4x2 + -49z2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '49z2' to each side of the equation.
4x2 + -49z2 + 49z2 = 0 + 49z2

Combine like terms: -49z2 + 49z2 = 0
4x2 + 0 = 0 + 49z2
4x2 = 0 + 49z2
Remove the zero:
4x2 = 49z2

Divide each side by '4'.
x2 = 12.25z2

Simplifying
x2 = 12.25z2

Take the square root of each side:
x = {-3.5z, 3.5z}

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