(2x+7)=(8x-2)=65

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Solution for (2x+7)=(8x-2)=65 equation:



(2x+7)=(8x-2)=65
We move all terms to the left:
(2x+7)-((8x-2))=0
We get rid of parentheses
2x-((8x-2))+7=0
We calculate terms in parentheses: -((8x-2)), so:
(8x-2)
We get rid of parentheses
8x-2
Back to the equation:
-(8x-2)
We get rid of parentheses
2x-8x+2+7=0
We add all the numbers together, and all the variables
-6x+9=0
We move all terms containing x to the left, all other terms to the right
-6x=-9
x=-9/-6
x=1+1/2

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