(2x+7)/8+x-2=(x-1)/2

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Solution for (2x+7)/8+x-2=(x-1)/2 equation: 


x in (-oo:+oo)

(2*x+7)/8+x-2 = (x-1)/2 // - (x-1)/2

(2*x+7)/8-((x-1)/2)+x-2 = 0

(2*x+7)/8+(-1*(x-1))/2+x-2 = 0

(2*(2*x+7))/(2*8)+(-1*8*(x-1))/(2*8)+(2*8*x)/(2*8)+(-2*2*8)/(2*8) = 0

2*(2*x+7)-1*8*(x-1)+2*8*x-2*2*8 = 0

16*x-4*x-32+22 = 0

12*x-32+22 = 0

12*x-10 = 0

(12*x-10)/(2*8) = 0

(12*x-10)/(2*8) = 0 // * 2*8

12*x-10 = 0

12*x-10 = 0 // + 10

12*x = 10 // : 12

x = 10/12

x = 5/6

x = 5/6

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