(2x+7)/5=-(1-3x)/8

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Solution for (2x+7)/5=-(1-3x)/8 equation: 



(2x+7)/5=-(1-3x)/8

We move all terms to the left:

(2x+7)/5-(-(1-3x)/8)=0

We add all the numbers together, and all the variables

(2x+7)/5-(-(-3x+1)/8)=0

We calculate fractions


2x/()+(-(-(-3x+1)*5)/()=0



We calculate terms in parentheses: +(-(-(-3x+1)*5)/(), so:

-(-(-3x+1)*5)/(

We multiply all the terms by the denominator


-(-(-3x+1)*5)



We calculate terms in parentheses: -(-(-3x+1)*5), so:

-(-3x+1)*5

We multiply parentheses

15x-5

Back to the equation:

-(15x-5)



We get rid of parentheses

-15x+5

Back to the equation:

+(-15x+5)



We get rid of parentheses

2x/()-15x+5=0

We multiply all the terms by the denominator


2x-15x*()+5*()=0

We add all the numbers together, and all the variables

2x-15x*()=0

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