(2x+7)/5=(9-3x)/6

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Solution for (2x+7)/5=(9-3x)/6 equation: 



(2x+7)/5=(9-3x)/6

We move all terms to the left:

(2x+7)/5-((9-3x)/6)=0

We add all the numbers together, and all the variables

(2x+7)/5-((-3x+9)/6)=0

We calculate fractions


2x/()+(-((-3x+9)*5)/()=0



We calculate terms in parentheses: +(-((-3x+9)*5)/(), so:

-((-3x+9)*5)/(

We multiply all the terms by the denominator


-((-3x+9)*5)



We calculate terms in parentheses: -((-3x+9)*5), so:

(-3x+9)*5

We multiply parentheses

-15x+45

Back to the equation:

-(-15x+45)



We get rid of parentheses

15x-45

Back to the equation:

+(15x-45)



We get rid of parentheses

2x/()+15x-45=0

We multiply all the terms by the denominator


2x+15x*()-45*()=0

We add all the numbers together, and all the variables

2x+15x*()=0

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