(2x+7)+(2x+8)+(2x)=(2x)+(2x)+(3x+1)

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Solution for (2x+7)+(2x+8)+(2x)=(2x)+(2x)+(3x+1) equation: 



(2x+7)+(2x+8)+(2x)=(2x)+(2x)+(3x+1)

We move all terms to the left:

(2x+7)+(2x+8)+(2x)-((2x)+(2x)+(3x+1))=0

We add all the numbers together, and all the variables

2x+(2x+7)+(2x+8)-(2x+2x+(3x+1))=0

We get rid of parentheses

2x+2x+2x-(2x+2x+(3x+1))+7+8=0



We calculate terms in parentheses: -(2x+2x+(3x+1)), so:

2x+2x+(3x+1)

We add all the numbers together, and all the variables

4x+(3x+1)

We get rid of parentheses

4x+3x+1

We add all the numbers together, and all the variables

7x+1

Back to the equation:

-(7x+1)



We add all the numbers together, and all the variables

6x-(7x+1)+15=0

We get rid of parentheses

6x-7x-1+15=0

We add all the numbers together, and all the variables

-1x+14=0

We move all terms containing x to the left, all other terms to the right

-x=-14

x=-14/-1

x=+14

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