(2x+7)(x-11)=0

Solution for (2x+7)(x-11)=0 equation:

(2x+7)(x-11)=0

We multiply parentheses ..

(+2x^2-22x+7x-77)=0

We get rid of parentheses

2x^2-22x+7x-77=0

We add all the numbers together, and all the variables

2x^2-15x-77=0

a = 2; b = -15; c = -77;
Δ = b2-4ac
Δ = -152-4·2·(-77)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-29}{2*2}=\frac{-14}{4}
=-3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+29}{2*2}=\frac{44}{4}
=11
$