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(2x+7)(9x)=0
We multiply parentheses
18x^2+63x=0
a = 18; b = 63; c = 0;
Δ = b2-4ac
Δ = 632-4·18·0
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-63}{2*18}=\frac{-126}{36} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+63}{2*18}=\frac{0}{36} =0 $
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