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(2x+7)(6x+9)=0
We multiply parentheses ..
(+12x^2+18x+42x+63)=0
We get rid of parentheses
12x^2+18x+42x+63=0
We add all the numbers together, and all the variables
12x^2+60x+63=0
a = 12; b = 60; c = +63;
Δ = b2-4ac
Δ = 602-4·12·63
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-24}{2*12}=\frac{-84}{24} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+24}{2*12}=\frac{-36}{24} =-1+1/2 $
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