(2x+7)(5-4x)=0

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Solution for (2x+7)(5-4x)=0 equation:



(2x+7)(5-4x)=0
We add all the numbers together, and all the variables
(2x+7)(-4x+5)=0
We multiply parentheses ..
(-8x^2+10x-28x+35)=0
We get rid of parentheses
-8x^2+10x-28x+35=0
We add all the numbers together, and all the variables
-8x^2-18x+35=0
a = -8; b = -18; c = +35;
Δ = b2-4ac
Δ = -182-4·(-8)·35
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-38}{2*-8}=\frac{-20}{-16} =1+1/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+38}{2*-8}=\frac{56}{-16} =-3+1/2 $

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