(2x+68)=(6x+28)

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Solution for (2x+68)=(6x+28) equation: 



(2x+68)=(6x+28)

We move all terms to the left:

(2x+68)-((6x+28))=0

We get rid of parentheses

2x-((6x+28))+68=0



We calculate terms in parentheses: -((6x+28)), so:

(6x+28)

We get rid of parentheses

6x+28

Back to the equation:

-(6x+28)



We get rid of parentheses

2x-6x-28+68=0

We add all the numbers together, and all the variables

-4x+40=0

We move all terms containing x to the left, all other terms to the right

-4x=-40

x=-40/-4

x=+10

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