(2x+68)=(4x-2)

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Solution for (2x+68)=(4x-2) equation: 



(2x+68)=(4x-2)

We move all terms to the left:

(2x+68)-((4x-2))=0

We get rid of parentheses

2x-((4x-2))+68=0



We calculate terms in parentheses: -((4x-2)), so:

(4x-2)

We get rid of parentheses

4x-2

Back to the equation:

-(4x-2)



We get rid of parentheses

2x-4x+2+68=0

We add all the numbers together, and all the variables

-2x+70=0

We move all terms containing x to the left, all other terms to the right

-2x=-70

x=-70/-2

x=+35

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