(2x+62)+(54-x)+(5x-20)=180

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Solution for (2x+62)+(54-x)+(5x-20)=180 equation: 



(2x+62)+(54-x)+(5x-20)=180

We move all terms to the left:

(2x+62)+(54-x)+(5x-20)-(180)=0

We add all the numbers together, and all the variables

(2x+62)+(-1x+54)+(5x-20)-180=0

We get rid of parentheses

2x-1x+5x+62+54-20-180=0

We add all the numbers together, and all the variables

6x-84=0

We move all terms containing x to the left, all other terms to the right

6x=84

x=84/6

x=14

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