(2x+6)2+(5x-7)2=(4x+2)2

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Solution for (2x+6)2+(5x-7)2=(4x+2)2 equation: 



(2x+6)2+(5x-7)2=(4x+2)2

We move all terms to the left:

(2x+6)2+(5x-7)2-((4x+2)2)=0

We multiply parentheses

4x+10x-((4x+2)2)+12-14=0



We calculate terms in parentheses: -((4x+2)2), so:

(4x+2)2

We multiply parentheses

8x+4

Back to the equation:

-(8x+4)



We add all the numbers together, and all the variables

14x-(8x+4)-2=0

We get rid of parentheses

14x-8x-4-2=0

We add all the numbers together, and all the variables

6x-6=0

We move all terms containing x to the left, all other terms to the right

6x=6

x=6/6

x=1

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