(2x+6)+(7x-4)=(10x-2)

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Solution for (2x+6)+(7x-4)=(10x-2) equation: 



(2x+6)+(7x-4)=(10x-2)

We move all terms to the left:

(2x+6)+(7x-4)-((10x-2))=0

We get rid of parentheses

2x+7x-((10x-2))+6-4=0



We calculate terms in parentheses: -((10x-2)), so:

(10x-2)

We get rid of parentheses

10x-2

Back to the equation:

-(10x-2)



We add all the numbers together, and all the variables

9x-(10x-2)+2=0

We get rid of parentheses

9x-10x+2+2=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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