(2x+6)(x-7)=x(2x-2)

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Solution for (2x+6)(x-7)=x(2x-2) equation: 



(2x+6)(x-7)=x(2x-2)

We move all terms to the left:

(2x+6)(x-7)-(x(2x-2))=0

We multiply parentheses ..

(+2x^2-14x+6x-42)-(x(2x-2))=0



We calculate terms in parentheses: -(x(2x-2)), so:

x(2x-2)

We multiply parentheses

2x^2-2x

Back to the equation:

-(2x^2-2x)



We get rid of parentheses

2x^2-2x^2-14x+6x+2x-42=0

We add all the numbers together, and all the variables

-6x-42=0

We move all terms containing x to the left, all other terms to the right

-6x=42

x=42/-6

x=-7

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