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(2x+6)(4x-24)=0
We multiply parentheses ..
(+8x^2-48x+24x-144)=0
We get rid of parentheses
8x^2-48x+24x-144=0
We add all the numbers together, and all the variables
8x^2-24x-144=0
a = 8; b = -24; c = -144;
Δ = b2-4ac
Δ = -242-4·8·(-144)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-72}{2*8}=\frac{-48}{16} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+72}{2*8}=\frac{96}{16} =6 $
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