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(2x+6)(3x-15)=0x=
We move all terms to the left:
(2x+6)(3x-15)-(0x)=0
We add all the numbers together, and all the variables
-1x+(2x+6)(3x-15)=0
We multiply parentheses ..
(+6x^2-30x+18x-90)-1x=0
We get rid of parentheses
6x^2-30x+18x-1x-90=0
We add all the numbers together, and all the variables
6x^2-13x-90=0
a = 6; b = -13; c = -90;
Δ = b2-4ac
Δ = -132-4·6·(-90)
Δ = 2329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{2329}}{2*6}=\frac{13-\sqrt{2329}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{2329}}{2*6}=\frac{13+\sqrt{2329}}{12} $
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